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How does the scaling configuration in Modbus configuration work?
The scaling calculation is based on differentiation. Example:
The frequency is internally (in the relay) stored as an integer value which also holds three decimal places, that is, 50.000 Hz is represented as 50000. This is a value too large to be represented with 16 bits (signed integer). Frequency is by default scaled with the points: (x1, y1) = (0, 0) and (x2, y2) = (10, 1) enabling it to be sent over Modbus.
See example calculation in attachment
The frequency is internally (in the relay) stored as an integer value which also holds three decimal places, that is, 50.000 Hz is represented as 50000. This is a value too large to be represented with 16 bits (signed integer). Frequency is by default scaled with the points: (x1, y1) = (0, 0) and (x2, y2) = (10, 1) enabling it to be sent over Modbus.
See example calculation in attachment
Julkaistu:Schneider Electric Suomi
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